How can I calculate the opening area of a arch type door where base is 1.6 metre & height is .35 metres?
If it is not a circular, then what is the dimension of top of the trapezoid ?
And what is the dimension from top of trapezoid to top of arc?
So, please use the following formulae:
*If the two sides which are not parallel have equal lengths, then the trapezoid is called an isosceles trapezoid. The base angles in an isosceles trapezoid are equal in measurement.
*The area of an isosceles (or any trapezoid) is equal to the average of the bases times the height. In the diagram to the right, b1 = segment AD, b2 = segment BC and h is the length of a line segment between AD and BC and perpendicular to them. The area is given as follows:
h*[b1+b2] / 2
*Length of circle arch
L = A * R
L = A * R
Where
L — length of circle arch,
R — radius of a circle,
A — the central angle expressed in radians.
So, for a circle:
A = 2*pi (360 degrees),
we shall receive L = 2*pi*R.
[If it is a circular ,then area will be like as under:
Assume the arch is a rectangle with a semi circl
