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Below is a an equation to calculate mass that will leak away at an allowable rate in 10 sec's this answer needs validation as well as the one below so I would appreciate ones help. Thanks

P := 14.7∙psi
Q := 4.5•10¯2 •cc/sec
Q := 1.59•10¯6 •ft³/sec
t := 10•sec
T := 519•R
R := 10.73•(ft³•psi)/(R•lbmol)

V :=Q•t
V := 1.59•10¯5• ft³ ....is this true?

N:=(P•V)/(R•T)
N:=4.197∙10¯8∙LBMOL ....is this true?


also

Chamber conditions:
P := 14.7∙psi + 6.4 ∙psi
P := 21.1
V:= .030865•ft³
R:= 10.73∙ (ft3∙psi)/(R∙lbmol)
T:= 519•R

Calculate the mass of air in the chamber:

N:=(P•V)/(R•T)
N:=1.16945∙10¯4∙LBMOL ..........is this true?

Thanks for any help.

One of us is making an error in unit conversion

I convert 4.5e-2 cc/sec to 1.59e- 6 cuft/sec.

The conversion used is 30.48 cm/ft - 28317 cc/cuft or 3.53e-5 cuft/cc

I did not check farther.

Niel Leon
engineering.com