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 A fluid making centrifugal movement in a cone Last Post 23 Sep 2012 05:15 AM by Nathaniel. 1 Replies. Sort: Oldest First Most Recent First
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melisw_7

New Member
Posts:1

 23 Sep 2012 03:11 AM We have a cone, standing horizontally. A fluid enters to cone from the larger cross-section and makes centrifugal movement. Fluid moves towards small cross-section. At the small cross-section part we have to separate some particles from the fluid by centrifugal force. I would like to know that will the separation be more efficient if we have a smaller or larger cross-section at the end? or for example, is a cylinder more efficient or not? And how can we prove that? Thanks
Nathaniel

Basic Member
Posts:193

 23 Sep 2012 05:15 AM Accepted Answer The equation for radial acceleration is given by the equation - Radial Acceleration = v^2 /r v = rotational speed x r so the radial acceleration as a function of rotational speed Radial acceleration = rotational speed ^ 2 x radius As a result the fluid is going to move from the small end of the cone to the large end and not the way you have indicated unless you have a very big driving force. Niel Leon engineering.com
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