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A fluid making centrifugal movement in a cone
Last Post 23 Sep 2012 05:15 AM by Nathaniel. 1 Replies.
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melisw_7
New Member
New Member
Posts:1

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23 Sep 2012 03:11 AM
    We have a cone, standing horizontally. A fluid enters to cone from the larger cross-section and makes centrifugal movement. Fluid moves towards small cross-section. At the small cross-section part we have to separate some particles from the fluid by centrifugal force.
    I would like to know that will the separation be more efficient if we have a smaller or larger cross-section at the end? or for example, is a cylinder more efficient or not?
    And how can we prove that?

    Thanks
    Nathaniel
    Basic Member
    Basic Member
    Posts:193

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    23 Sep 2012 05:15 AM
    • Accepted Answer
    The equation for radial acceleration is given by the equation - Radial Acceleration = v^2 /r

    v = rotational speed x r

    so the radial acceleration as a function of rotational speed

    Radial acceleration = rotational speed ^ 2 x radius

    As a result the fluid is going to move from the small end of the cone to the large end and not the way you have indicated unless you have a very big driving force.

    Niel Leon
    engineering.com
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