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Need your help please! Fluid Dynamics Question
Last Post 01 Sep 2013 10:43 PM by Kanfoosh. 2 Replies.
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Engr.Azher
New Member
New Member
Posts:2

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04 Jul 2012 08:37 AM

    I actually want to calculate the head loss, for this i need to calculate Reynold number, How do I?

    V= 2m/sec
    dia of pipe = 6 inch = 0.156 m
    kinematic viscosity of water at 30 C = 10^-6 m^2/sec

    Re = 7745.8 x velcoity x dia of pipe /Kinematic viscosity

    Above formula is correct? if so then how 7745.8 number comes? I know this is Imperial Unit but how it comes?

    Please guide me.
    Niel
    Basic Member
    Basic Member
    Posts:193

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    05 Jul 2012 02:33 AM
    Reynolds number is unit-less. If your are working in the Imperial Unit world you need to make use of a constant to eliminate the units. There should not be any corrections in the SI or metric system if used properly.

    Niel Leon
    engineering.com
    Kanfoosh
    New Member
    New Member
    Posts:2

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    01 Sep 2013 10:43 PM
    Not sure where you got the constant 7745.8?

    Given the variables in your post it's a straightforward calculation Re=2*0.156*(1/ 10^-6) = 312000
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