Engr.Azher
New Member Posts:2

04 Jul 2012 08:37 AM 

I actually want to calculate the head loss, for this i need to calculate Reynold number, How do I? V= 2m/sec dia of pipe = 6 inch = 0.156 m kinematic viscosity of water at 30 C = 10^6 m^2/sec Re = 7745.8 x velcoity x dia of pipe /Kinematic viscosity Above formula is correct? if so then how 7745.8 number comes? I know this is Imperial Unit but how it comes? Please guide me.





Niel
Basic Member Posts:193

05 Jul 2012 02:33 AM 

Reynolds number is unitless. If your are working in the Imperial Unit world you need to make use of a constant to eliminate the units. There should not be any corrections in the SI or metric system if used properly. Niel Leon engineering.com 




Kanfoosh
New Member Posts:2

01 Sep 2013 10:43 PM 

Not sure where you got the constant 7745.8? Given the variables in your post it's a straightforward calculation Re=2*0.156*(1/ 10^6) = 312000




